2 solutions

  • 1
    @ 2025-7-30 15:04:04
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
        double n,m;cin>>n>>m;
        int y=n/10*m;
        int g=y%10;
        if(g>=5)
        {
            y=y+10-g;
        }
        else y-=g;
        cout<<y;
        return 0;
    }
    
    • 0
      @ 2025-8-15 15:15:12
      #include<bits/stdc++.h>
      using namespace std;
      double a;
      double b;
      int main(){
      	cin>>a>>b;
      	int t=a*b/10;
      	int x=round(t);
      	cout<<x;
      	
      	
      	return 0;
      } 
      
      • 1

      Information

      ID
      2819
      Time
      1000ms
      Memory
      64MiB
      Difficulty
      6
      Tags
      # Submissions
      46
      Accepted
      16
      Uploaded By