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按照题目描述去模拟即可,为了方便,可以统一转化大小写以后再进行偏移.
代码实现
#include<bits/stdc++.h> using namespace std; int main() { string s1,s2; cin>>s1>>s2; string s; for(int i=0;i<s2.size();i++) { char a=tolower(s2[i]),b=tolower(s1[i%s1.size()]); //统一大小写 char c=(a-'a'-(b-'a')+26)%26+'a'; //进行规则变换 if(s2[i]<'a') c=toupper(c); //和原字符保持大小写 s+=c; } cout<<s; }
- 1
Information
- ID
- 1094
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By