1 solutions

  • 0
    @ 2025-3-22 11:59:02

    #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

    • 1

    Information

    ID
    1927
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    8
    Tags
    # Submissions
    1
    Accepted
    1
    Uploaded By