3 solutions

  • 0
    @ 2025-5-5 9:17:20
    #include<bits/stdc++.h>
    using namespace std;
    int a[1145];
    int main()
    {
    	int n,d;
    	cin>>n>>d;
    	int id=0;
    	while(n){
    		a[id++]=n%d;
    		n/=d;
    	}
    	reverse(a,a+id);
    	for(int i=0;i<id;i++) cout<<a[i];
    	return 0;
    }
    
    • 0
      @ 2024-11-30 15:14:58
      #include<bits/stdc++.h>
      using namespace std;
      int a[100001];
      int main()
      {
      	int num=0,j=0,sum=1;
      	cin>>num>>j;
      	while(num!=0){
      		a[sum]=num%j;
      		num=(num-a[sum])/j;
      		sum++;
      	}
      	for(int i=sum-1;i>=1;i--){
      		cout<<a[i];
      	}
      	return 0;
      }
      
      
      • 0
        @ 2024-4-21 15:41:53
        #include<bits/stdc++.h>
        using namespace std;
        int a[100001];
        int main()
        {
        	int num=0,j=0,sum=1;
        	cin>>num>>j;
        	while(num!=0){
        		a[sum]=num%j;
        		num=(num-a[sum])/j;
        		sum++;
        	}
        	for(int i=sum-1;i>=1;i--){
        		cout<<a[i];
        	}
        	return 0;
        }
        
        • 1

        Information

        ID
        153
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        3
        Tags
        (None)
        # Submissions
        22
        Accepted
        15
        Uploaded By