1 solutions

  • 0
    @ 2025-8-22 16:13:20
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	string s1,s2;
    	cin>>s1>>s2;
    	int n=s1.size(),m=s2.size();
    	s1=" "+s1;
    	s2=" "+s2;
    	int j=1;
    	for(int i=1;i<=n;i++,j++)
    	{
    		while(s1[i]!=s2[j]) //不相同的时候第二个串就一直往后走 
    		{
    			j++;
    		}
    		cout<<j<<" "; 
    	}
    	return 0;
    }
    
    
    • 1

    Information

    ID
    2414
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    12
    Accepted
    3
    Uploaded By