1 solutions

  • 0
    @ 2025-4-26 13:58:11
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n,x;
    	cin>>n>>x;
    	string s;
    	while(n)
    	{
    		int ge=n%x; //计算余数
    		if(ge<10) s=s+char('0'+ge); 
    		else s=s+char('A'+ge-10);
    		n/=x; //更新商 
    	}
    	reverse(s.begin(),s.end());
    	cout<<s;
    	return 0;
    }
    
    
    • 1

    Information

    ID
    1195
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    28
    Accepted
    5
    Uploaded By