2 solutions
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4
#include<bits/stdc++.h> using namespace std; int main() { string a; cin>>a; int t=0; int c=1; int n=a.size(); for(int i=0;i<n-1;i++) { if(a[i]>='0'&&a[i]<='9') { t=t+(a[i]-'0')*c; //累加 c++;//增加乘 } } int q=t%11;//计算余数 if(q==10&&a[n-1]=='X'||q==a[n-1]-'0') cout<<"Right"; //正确匹配 else { if(q==10) { a[n-1]='X';//最后余数10为x } else { a[n-1]=q+'0'; //更改成正确的数字 } cout<<a; } return 0; }
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0
#include<bits/stdc++.h> using namespace std; string s; int main(){ cin>>s; int n=s.size(); int cnt=0; cnt=cnt+s[1]*1; for(int i=1;i<n;i++){ if(s[i]=='-'){ continue; }else{ cnt=cnt+s[i]*2; } } int k=cnt%11; char X; if(cnt%11==10){ X='X'; } if(s[n-1]==k||s[n-1]==X){ cout<<"Right"; }else{ s[n-1]=k; for(int i=0;i<n;i++){ cout<<s[i]; } } return 0; }
- 1
Information
- ID
- 102
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 5
- Tags
- (None)
- # Submissions
- 137
- Accepted
- 24
- Uploaded By