2 solutions

  • 1
    @ 2025-8-22 13:40:35
    #include<bits/stdc++.h>
    using namespace std;
    string s;
    int main(){
    	cin>>s;
    	int n=s.size();
    	for(int i=0;i<n;i++){
    		if(s[i]>='a'&&s[i]<='z'){
    			s[i]=s[i]+'A'-'a';
    		}else if(s[i]>='A'&&s[i]<='Z'){
    			s[i]=s[i]+'a'-'A'; 
    		}
    	}
    	cout<<s; 
    	return 0;
    }
    
    
    • -1
      @ 2024-9-11 18:45:58
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
      	string n;
      	cin>>n;
      	for(int i=0;i<n.size();i++)
      	{
      		if(n[i]>='A'&&n[i]<='Z')n[i]=n[i]-'A'+'a';
      		else if(n[i]>='a'&&n[i]<='z')n[i]=n[i]-'a'+'A';
      	 } 
      	cout<<n;
      	return 0;
      }
      
      
      • 1

      Information

      ID
      101
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      42
      Accepted
      19
      Uploaded By