1 solutions

  • 1
    @ 2024-8-13 17:30:21
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
        char c;
        string s;
        while(cin>>c>>s)
        {
            int n=s.size();
            int cnt=0;
            if(c>='A'&&c<='Z')
            {
                c=c-'A'+'a';
            }
            for(int i=0;i<n;i++)
            {
                if(s[i]>='A'&&s[i]<='Z')
                {
                    s[i]=s[i]-'A'+'a';
                }
                if(s[i]==c)
                {
                    cnt++;
                } 
            }
            cout<<fixed<<setprecision(5)<<(cnt*1.0/n)<<endl;
        }
        return 0;
    }
    
    • 1

    Information

    ID
    98
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    32
    Accepted
    20
    Uploaded By