1 solutions
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1
#include<bits/stdc++.h> using namespace std; const int N=100010; char s[N]; int main() { int k; cin>>k; cin.getline(s,N); cin.getline(s,N); int n=strlen(s); for(int i=0;i<n;i++) { int j=i; while(j<n&&s[i]==s[j]) j++; j--; int len=j-i+1; if(len>=k) { cout<<s[i]; return 0; } i=j; } cout<<"No"; return 0; }
- 1
Information
- ID
- 924
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 77
- Accepted
- 25
- Uploaded By