2 solutions

  • 3
    @ 2024-7-25 15:05:09
    #include<bits/stdc++.h>
    using namespace std;
    const int N=100001;
    char a[N];
    char b[N];
    int main()
    {
    	cin>>a;
    	int n=strlen(a);
    	for(int i=0;i<=n;i++)
    	{
    		b[i]=a[i]+a[i+1];
    		if(i==n-1)
    		{
    			b[i]=a[0]+a[i];
    		}
    	}
    	cout<<b;
    	return 0;
    }
    
    • 1
      @ 2025-1-21 10:35:43
        #include<bits/stdc++.h>
        using namespace std;
        const int N=100001;
        char a[N];
        char b[N];
        int main()
        {
        	cin>>a;
        	int n=strlen(a);
        	for(int i=0;i<=n;i++)
        	{
        		b[i]=a[i]+a[i+1]
        		if(i==n-1)
        		{
        			b[i]=a[0]+a[i];
        		}
        	}
        	cout<<b;
        	return 0;
        }
      
      
      • 1

      Information

      ID
      917
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      56
      Accepted
      31
      Uploaded By