3 solutions
-
-4
#include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; int a[n+10][n+10]; for(int t=1;t<=(n+2-1)/2;t++){ for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ if((i>=t && i<=n+1-t) && (j>=t && j<=n+1-t)){ a[i][j]=t; } }
} } for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ cout<<a[i][j]<<" "; } cout<<"\n"; }
return 0; }
- 1
Information
- ID
- 72
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 90
- Accepted
- 40
- Uploaded By