10 solutions

  • 1
    @ 2025-1-12 15:06:58
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int m,n;
    	cin>>m>>n;
    	int t=m;
    	int s=0;
    	while(t<=n) //枚举m到n之间的所有数 
    	{
    		if(t%17==0) //判断17的倍数 
    		{
    			s+=t;
    		}
    		t++;
    	}
    	cout<<s;
    	return 0;
    }
    
    • 1
      @ 2024-12-15 16:30:29
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
      	int m,n;
      	cin>>m>>n;
      	int s=0;
      	for(int i=m;i<=n;i++)
      	{
      		if(i%17==0)
      		s+=i;
      	}
      	cout<<s;
      	return 0;
      }
      
      • 0
        @ 2025-3-22 11:49:55

        #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

        • 0
          @ 2025-3-22 11:49:46

          #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

          • 0
            @ 2025-3-22 11:49:30

            #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

            • 0
              @ 2025-3-22 11:49:27

              #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

              • 0
                @ 2025-3-22 11:49:15

                #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

                • 0
                  @ 2025-3-22 11:49:09

                  #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

                  • 0
                    @ 2025-3-22 11:49:01

                    #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

                    • 0
                      @ 2025-3-22 11:48:33

                      #include<bits/stdc++.h> using namespace std; int main() { int m,n; cin>>m>>n; int t=m; int s=0; while(t<=n) //枚举m到n之间的所有数 { if(t%17==0) //判断17的倍数 { s+=t; } t++; } cout<<s; return 0; }

                      • 1

                      Information

                      ID
                      47
                      Time
                      1000ms
                      Memory
                      256MiB
                      Difficulty
                      1
                      Tags
                      (None)
                      # Submissions
                      179
                      Accepted
                      61
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