2 solutions

  • 1
    @ 2025-4-26 15:11:59
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int a,b;
    	cin>>a>>b;
    	int t=b/a; //计算应该是第几个字母
    	if(b%a==0) t--; //如果是整倍数,商需要减一
    	char c='A'+t;
    	cout<<c; 
    	return 0;
    }
    
    • -2
      @ 2025-8-11 15:38:23
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
      	int n,m;
      	cin>>n>>m;
      	char a=(m/n)+'A'-1;
      	if(m%n!=0) a++;
      	cout<<a;
      	return 0;
      }
      
      • 1

      Information

      ID
      2404
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      110
      Accepted
      37
      Uploaded By