5 solutions

  • 1
    @ 2025-5-19 19:33:44
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	double xa,ya,xb,yb;
    	cin>>xa>>ya>>xb>>yb;
    	double a=xa-xb;
    	double b=ya-yb;
    	double c=sqrt(a*a+b*b);
    	cout<<fixed<<setprecision(3)<<c;
    	return 0;
    }
    
    

    这叫做实力!!!!

    Information

    ID
    853
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    224
    Accepted
    57
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