2 solutions
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1
#include<bits/stdc++.h> using namespace std; int a[100010],b[100010],k; int main(){ int n,m,k; cin>>n>>m>>k; for(int i=1;i<=n;i++)cin>>a[i]; for(int i=1;i<=n;i++)cin>>b[i]; for(int l=1,r=m;l<=n&&r>=1;){ if(a[l]+b[r]>k)r--; else if(a[l]+b[r]<k)l++; else{ cout<<l-1<<' '<<r-1; return 0; } } return 0; }
Information
- ID
- 2881
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 5
- Tags
- # Submissions
- 11
- Accepted
- 3
- Uploaded By