1 solutions

  • 0
    @ 2025-8-29 11:22:19
    #include<bits/stdc++.h>
    using namespace std;
    const int N=2e5+10;
    vector<int> g[N];
    int cnt[N],st[N];
    void dfs(int u,int fa,int c)
    {
    	st[u]=c;//表示u的点的状态
    	cnt[c]++;
    	for(auto j:g[u])
    	{
    		if(j==fa) continue;
    		dfs(j,u,c^1);//奇偶状态互换	
    	} 
    }
    int main()
    {
    	int n;
    	cin>>n;
    	for(int i=1;i<n;i++)
    	{
    		int a,b;
    		cin>>a>>b;
    		g[a].push_back(b);
    		g[b].push_back(a);
    	}
    	dfs(1,-1,0);
    	for(int i=1;i<=n;i++)
    	{
    		cout<<cnt[st[i]]<<" ";
    	}
    	return 0;	
    }
    
    

    Information

    ID
    2569
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    10
    Tags
    # Submissions
    4
    Accepted
    2
    Uploaded By