5 solutions
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-1
#include<bits/stdc++.h> using namespace std; const int N=210; int a[N],b[N]; int main() { int n,na,nb; cin>>n>>na>>nb; for(int i=1;i<=na;i++) cin>>a[i]; for(int i=1;i<=nb;i++) cin>>b[i]; for(int i=na+1;i<=n;i++) a[i]=a[i-na]; for(int i=nb+1;i<=n;i++) b[i]=b[i-nb]; int res=0; for(int i=1;i<=n;i++) { if(a[i]==0&&b[i]==2||a[i]==2&&b[i]==5||a[i]==5&&b[i]==0) { res++; }else if(a[i]==b[i])//相同 { ; }else { res--; } } if(res>0) cout<<"A"; else if(res<0) cout<<"B"; else cout<<"draw"; return 0; }
Information
- ID
- 2144
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 37
- Accepted
- 16
- Uploaded By